Biorthogonal Systems in Banach Spaces by Petr Hajek, Vicente Montesinos Santalucia, Jon Vanderwerff,

By Petr Hajek, Vicente Montesinos Santalucia, Jon Vanderwerff, Vaclav Zizler

One of the elemental questions of Banach area concept is whether or not each Banach house has a foundation. an area with a foundation offers us the sensation of familiarity and concreteness, and maybe an opportunity to aim the category of all Banach areas and different problems.

The major pursuits of this publication are to:

• introduce the reader to a couple of the fundamental options, effects and purposes of biorthogonal structures in endless dimensional geometry of Banach areas, and in topology and nonlinear research in Banach spaces;

• to take action in a way obtainable to graduate scholars and researchers who've a starting place in Banach area theory;

• reveal the reader to a few present avenues of study in biorthogonal structures in Banach spaces;

• supply notes and routines regarding the subject, in addition to suggesting open difficulties and attainable instructions of study.

The meant viewers can have a simple heritage in sensible research. The authors have integrated quite a few workouts, in addition to open difficulties that time to attainable instructions of study.

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Extra info for Biorthogonal Systems in Banach Spaces

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Let X be a Banach space, and let G be a subset of X. Let H be the set of accumulation points of G, and suppose that X is the closed linear span of H. Then, given any x ∈ X and any sequence of numbers (an ) with |an | = ∞ and lim an = 0, there is a sequence of signs and distinct elements gn ∈ G so that n ∞ x= n an gn . n=1 Before proving this, we present the following corollary that answers a question of Z. Lipecki. 59 (Fremlin and Sersouri [FrSe88]). Suppose X is a separable Banach space. Then every ω-independent family in X is countable.

A biorthogonal system {zn ; zn∗ }∞ n=1 in X × X is called a ∞ flattened perturbation with respect to (n(j), A(j))j=1 of another biorthogonal ∗ system {xn ; x∗n }∞ n=1 in X × X if, for every j ∈ N, (i) {zn ; zn∗ }n∈A(j) is a block perturbation of {xn ; x∗n }n∈A(j) , and (ii) zn∗ − x∗n(j) ≤ εj / xn(j) for n ∈ A(j), j = 1, 2, . , where (εj )∞ j=1 is a sequence of positive numbers such that ∞ j=1 εj < ∞. Flattened perturbations are easy to construct. Just define, for each j ∈ N, an invertible operator from span{x∗n ; n ∈ A(j)} onto itself that sends each x∗n to some vector close to x∗n(j) .

N = 2, 3, . . , n = 1, 2, . . , n = 1, 2, . . 5 Strong M-bases 23 We compute that f2n−1 (z) = 0 for all n. If {xn ; fn } is a strong M-basis, then z ∈ span{f2n (z)x2n } and thus z ∈ span{x2n }. However, put ∞ g = h2 + i=1 1 h2i−1 . 2i Then g(z) = 12 and g(x2n ) = 0. Thus z cannot be in span{x2n }. This contradiction shows that {xn ; fn } is not a strong M-basis. 35. Let {xn }∞ n=1 be an M-basis for a Banach space X. Then the following are equivalent: (i) {xn } is a strong M-basis for X. (ii) [PlRe83] span{xn ; n ∈ A} ∩ span{xn ; n ∈ B} = span{xn ; n ∈ A ∩ B} for every A ⊂ N, B ⊂ N.

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